I need steering again-Aren't the input(cathode sides grounded anyway - thru the safety switches? My head is starting to hurt!Grounding the input side of the diode matrix would be a Bad Thing, as you'd be bypassing the diode function which is to prevent current backflow from the 'safety circuits', one to another.
As far as I know, there's only the wiring diagram.
I believe that the starter lockout switch is the clutch switch.
Anyhow, the RED/BLACK wire from the CDI must "see" a ground for the bike to run; the ground can come from several paths.
The starting circuit relay can pick up a ground from either the starter lockout ("clutch safety") switch or the neutral swith.
Switching logic prevents engine operation with the bike in gear, clutch lever out, and sidestand down.
And this is why I wonder if more than one sw to gnd or neg needs to be completed....
I don't fully understand your query; regardless . . . if you just want to defeat some safety switches, plenty of how-to articles, posts, even video clips are up on the 'Net.And this is why I wonder if more than one sw to gnd or neg needs to be completed....
Looks like the ignition would be enabled, but . . . what about the starter circuit relay?Getting back to Jim's original question, though - I think the answer is yes, grounding the input side of the diode matrix (jumping the red/black and the black/yellow wires coming out of the CDI connector) would disable the safety circuits. The starter circuit might not work, though - sort of like scenario 5. Still confused about that.
I see what you mean.I've modified the wiring diagram by grounding the input side of the diodes (at the CDi connector; red circle). That effectively removes the diodes and all wires leading to and from them.
It looks to me like there is no ground circuit for the starter circuit relay if the bike is in gear or the clutch lever is out. Scenario 5.
Do you see the same?